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4emix
@4emix
July 2022
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1-3
2-2
3-1
4-2
5-3
6-3
7-2
8-2
9-1,3,4
10\ А-4, Б-2, В-3, Г-2
11.
С2H4 + HCl = C2H5Cl
CH4 = C + 2H2
C6H6 + Br2 = C6H5Br + HBr
12/
решение:
7,5 г х л
2C2Н6 + 7O2 →4CO2 ↑ + 6Н2О
60 г 89,6 л
х = 7,5 г ∙ 89,6 л\60 г = 11,2 л
ответ: V (СO2) = 11,2л
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Verified answer
1-32-2
3-1
4-2
5-3
6-3
7-2
8-2
9-1,3,4
10\ А-4, Б-2, В-3, Г-2
11.
С2H4 + HCl = C2H5Cl
CH4 = C + 2H2
C6H6 + Br2 = C6H5Br + HBr
12/
решение:
7,5 г х л
2C2Н6 + 7O2 →4CO2 ↑ + 6Н2О
60 г 89,6 л
х = 7,5 г ∙ 89,6 л\60 г = 11,2 л
ответ: V (СO2) = 11,2л