ПОМОГИТЕ!! ОЧЕНЬ МНОГО БАЛЛОВ!!!!!!!!!!!!!!!!. Created by Ann0310. algebra-ru

ПОМОГИТЕ!! ОЧЕНЬ МНОГО БАЛЛОВ!!!!!!!!!!!!!!!!...

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1)(√a-√b)³(√a+√b)³/(√a+√b)³+2a√a+b√b=(√a-√b)³+2a√a+b√b=
=a√a-3a√b+3√ab-b√b+2a√a+b√b=3a√a-3a√b+3√ab
2)(3a√a-3a√b+3√ab):(3a²+3b√(ab))=3√a(a-√(ab)+b)/3√a(a√a+b√b)=
=(a-√ab+b)/(√a+√b)(a-√(ab)+b)=1/(√a+√b)
3)1/(√a+√b)+√a(√b-√a)/√a(a-b)=1/(√a+√b)-(√a-√b)/(√(a-√b)(√a+√b)=
=1/(√a+√b)-1/(√a+√b)=0

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LFP

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Использованы формулы:
куб разности,
разность квадратов,
сумма кубов и вынесение общего множителя за скобки...

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