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cake7
@cake7
August 2022
1
7
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помогите очень нужно!!!!
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ludmilagena
Verified answer
1) 1AE2 =
1
101
0 11
10 0
010
(2cc) = 15342 (8cc)
1C1C =
1
110
0 00
01 1
100
(2cc)
=
16034 (8cc)
2)
67 (10cc) =64+2+1=2^6+2^1+2^0 =1000011 (2cc)
F9=1111 1001 (2cc) (шесть единиц)
333 (8сс) =11 011 011 (шесть единиц)
1110 0111 < 1111 1001
ответ: b) F9
3)
504 |16
496 |----
----- | 31 |16
8
16 |---- 504 (10cc) =1F8 (16cc) =
1 11
11 1
000
(2cc) =770 (8cc)
----
1
15
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Answers & Comments
Verified answer
1) 1AE2 =1 1010 1110 0010 (2cc) = 15342 (8cc)1C1C = 1 1100 0001 1100 (2cc) =16034 (8cc)
2)
67 (10cc) =64+2+1=2^6+2^1+2^0 =1000011 (2cc)
F9=1111 1001 (2cc) (шесть единиц)
333 (8сс) =11 011 011 (шесть единиц)
1110 0111 < 1111 1001
ответ: b) F9
3)
504 |16
496 |----
----- | 31 |16
8 16 |---- 504 (10cc) =1F8 (16cc) =1 1111 1000 (2cc) =770 (8cc)
---- 1
15