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vask5
@vask5
July 2022
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помогите
очень очень надо
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Удачник66
Verified answer
Замена 2^x - 1 = y
y + 1 + 9/y > 7
y^2 + y - 7y + 9 > 0
y^2 - 6y + 9 > 0
(y - 3)^2 > 0
Это неравенство верно при любом y, кроме y = 3
2^x ≠ 3
x ≠ log2(3)
Ответ: x ∈ (-oo; log2(3)) U (
log2(3); +oo
)
2 votes
Thanks 1
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Answers & Comments
Verified answer
Замена 2^x - 1 = yy + 1 + 9/y > 7
y^2 + y - 7y + 9 > 0
y^2 - 6y + 9 > 0
(y - 3)^2 > 0
Это неравенство верно при любом y, кроме y = 3
2^x ≠ 3
x ≠ log2(3)
Ответ: x ∈ (-oo; log2(3)) U (log2(3); +oo)