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zilolarashidova
@zilolarashidova
July 2022
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Помогите, очень срочно надо плииз.
(x^2-3x)^2+3(x^2-3x)-28=0
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Answers & Comments
nadiasmile4
Пусть х^2-3х=у, тогда у^2+3у-28=0, D=9+112=121, y=(-3+11)/2=4, y=(-3-11)/2=-7
х^2-3х=4, х^2-3х-4=0, D=9+16=25, x=(3+5)/2=4, x=(3-5)/2=-1
x^2-3x=-7, x^2-3x+7=0, D=9-28, D<0, корней н
ет.
Ответ: 4; -1.
1 votes
Thanks 1
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Answers & Comments
х^2-3х=4, х^2-3х-4=0, D=9+16=25, x=(3+5)/2=4, x=(3-5)/2=-1
x^2-3x=-7, x^2-3x+7=0, D=9-28, D<0, корней нет.
Ответ: 4; -1.