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pashaoghly
@pashaoghly
August 2022
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Помогите очень срочно.
найдите скалярное произведение векторов a×b если [а]=4, [b]=корень 3 и угол (a^b) на 45
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kitrulit
а*b=IaI*IbI*cos(a,b)
a*b=4*√3*cos30=4√3*√3/2=6
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pashaoghly
А как 6 нашли?
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Answers & Comments
а*b=IaI*IbI*cos(a,b)
a*b=4*√3*cos30=4√3*√3/2=6