Помогите. Опр. массу 1 л азота(N2), CH4 и CO2. Created by AlinaKot123. himiya-ru

Помогите. Опр. массу 1 л азота(N2), CH4 и CO2...

October 2021 1 9 Report

Помогите. Опр. массу 1 л азота(N2), CH4 и CO2

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Ботаник122 V(N2)=V/Vm=1/22.4=0.044....
m(N2)=v*M=0.044..*28=1.25 грамм.

v(CH4)=V/Vm=1/22.4=0.044...
m(CH4)=v*M=0.044..*16≈0.714 грамм.

v(CO2)=1/22.4=0.044...
m(CO2)=v*M=0.044..*44≈1.96 грамм.

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