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. Логарифм 1 по любому допустимому основанию равен 0.
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Answers & Comments
2.![\sqrt[n]{a\cdot b} = a^{\frac{1}{n}}\ \cdot b^{\frac{1}{n}} = \boxed{(ab)^{\frac{1}{n}}} \sqrt[n]{a\cdot b} = a^{\frac{1}{n}}\ \cdot b^{\frac{1}{n}} = \boxed{(ab)^{\frac{1}{n}}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Ccdot%20b%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5C%20%5Ccdot%20b%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%20%3D%20%5Cboxed%7B%28ab%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%7D)
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