Verified answer

(k^2/3)^-5 / (k^1/6*k^1/2)

(a^m)^n = a^(mn)

a^m*a^n = a^(m+n)

a^m/a^n = a^(m - n)

(k^-10/3)*k^-1/6*k^-1/2 = k^(-10/3 - 1/6 - 1/2) = k^(-20/6 - 1/6 - 3/6) = k^-24/6

Ответ:

(k^2/3)^-5 / (k^1/6*k^1/2)

(a^m)^n = a^(mn)

a^m*a^n = a^(m+n)

a^m/a^n = a^(m - n)

(k^-10/3)*k^-1/6*k^-1/2 = k^(-10/3 - 1/6 - 1/2) = k^(-20/6 - 1/6 - 3/6) = k^-24/6