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anna1834
@anna1834
August 2022
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555alina5554
#1 а) 5(а+2)+(а-2)=5а+10+а-2=6а+8
Б) 2x(x+1)-4x(2-x)=2x²+2k-8x+4x²=6x²+2-8x
B) x(x²+x) - (x²+x+1)= x³+x²-x²-x-1=x³-x-1
Г)2y²(6y-1)+3y(y-4y²)=12y³-2y²+3y²-12y³=y²
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Задание 1.
а) 5 (а + 2) + (а - 2) = 5а + 10 + а - 2 = 6а + 8
б) 2х (х + 1) - 4х (2 - х) = 2х^2 + 2х - 8х + 8х^2 = 10х^2 - 6х
в) х (х^2 + х) - (х^2 + х + 1) = х^3 + х^2 - х^2 - х - 1 = х^3 - х - 1
г) 2у^2 (6у - 1) + 3у (у - 4у^2) = 12у^3 - 2у^2 + 3у^2 - 12у^3 = у^2
Задание 2.
(а^4 - а^3b + a^2b^2 - ab^3)a^2b = a^6b - a^5b^2 + a^4b^3 - a^3b^4
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Answers & Comments
Б) 2x(x+1)-4x(2-x)=2x²+2k-8x+4x²=6x²+2-8x
B) x(x²+x) - (x²+x+1)= x³+x²-x²-x-1=x³-x-1
Г)2y²(6y-1)+3y(y-4y²)=12y³-2y²+3y²-12y³=y²
а) 5 (а + 2) + (а - 2) = 5а + 10 + а - 2 = 6а + 8
б) 2х (х + 1) - 4х (2 - х) = 2х^2 + 2х - 8х + 8х^2 = 10х^2 - 6х
в) х (х^2 + х) - (х^2 + х + 1) = х^3 + х^2 - х^2 - х - 1 = х^3 - х - 1
г) 2у^2 (6у - 1) + 3у (у - 4у^2) = 12у^3 - 2у^2 + 3у^2 - 12у^3 = у^2
Задание 2.
(а^4 - а^3b + a^2b^2 - ab^3)a^2b = a^6b - a^5b^2 + a^4b^3 - a^3b^4