1. 2sin(π/4)-3tg(-π/6)-4sin(2π)-2cos(-π/4)=
√2+ √3-√2= √3
2. 4cos(π/3)-cos(2π)+3ctg(-π/3)-2sin(-π/3)=
2-1-√3+ √3=1
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Answers & Comments
1. 2sin(π/4)-3tg(-π/6)-4sin(2π)-2cos(-π/4)=
√2+ √3-√2= √3
2. 4cos(π/3)-cos(2π)+3ctg(-π/3)-2sin(-π/3)=
2-1-√3+ √3=1