Ответ:
1)
2)
3)
4)
1) 2x(a+b)+y(a+b)=(a+b)(2x+y)
2) 3a(x-y)-b(x-y)=(x-y)(3a-b)
3) 4c²(m+n)+d(m+n)=(m+n)(4c²+d)
1) ab+a=a(a+b)
2) a³b-a=a(a²b-1)
3) x³y²-y²=y²(x³-1)
4) 2ab-4a=2a(b-2)
5) 27y⁴-18y²=9y²(3y²-2)
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1)
2)
3)
4)
1) 2x(a+b)+y(a+b)=(a+b)(2x+y)
2) 3a(x-y)-b(x-y)=(x-y)(3a-b)
3) 4c²(m+n)+d(m+n)=(m+n)(4c²+d)
1) ab+a=a(a+b)
2) a³b-a=a(a²b-1)
3) x³y²-y²=y²(x³-1)
4) 2ab-4a=2a(b-2)
5) 27y⁴-18y²=9y²(3y²-2)