M(CaCO3) = 40+12+16*3 = 100 g/mol
W(Ca) = 40/100*100% = 40%
W(C) = 12/100*100% = 12 %
W(O) = 16*3 / 100*100% = 48%
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M(CaCO3) = 40+12+16*3 = 100 g/mol
W(Ca) = 40/100*100% = 40%
W(C) = 12/100*100% = 12 %
W(O) = 16*3 / 100*100% = 48%