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DjSergeyGolovorez
@DjSergeyGolovorez
August 2022
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Помогите плз,очень надо!!!!
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mikael2
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С²-9/с*1/(с-3)=(с+3)/с=1+3/с
1-с/3+1+с/3=2
6x-3x+3≤2+5x -2x≤-1 x≥1/2
x/4+x/8=2x/8+x/8=3x/8=3/2 x=3/2*8/3=4
x1*x2=72 x2=x1+6 x1(x1+6)=72 x1²+6x1-72=0 корни по Виетту
6; -12
точки пересечения -x²+1=x-1 -x²-x+2=0 x²+x-2=0 корни -2;+1
y1=-72/2=-36 y2=72/1=72
20/4√5²=20/4*5=1
---------------- -2----------------4--------------- x∈(-∞;-2)(2;4)(4;∞)
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Answers & Comments
Verified answer
С²-9/с*1/(с-3)=(с+3)/с=1+3/с1-с/3+1+с/3=2
6x-3x+3≤2+5x -2x≤-1 x≥1/2
x/4+x/8=2x/8+x/8=3x/8=3/2 x=3/2*8/3=4
x1*x2=72 x2=x1+6 x1(x1+6)=72 x1²+6x1-72=0 корни по Виетту
6; -12
точки пересечения -x²+1=x-1 -x²-x+2=0 x²+x-2=0 корни -2;+1
y1=-72/2=-36 y2=72/1=72
20/4√5²=20/4*5=1
---------------- -2----------------4--------------- x∈(-∞;-2)(2;4)(4;∞)