wieslawlozickip5w1nd Ответ:Объяснение:1)(4x+0,1y)³= 64x³+4,8x²y+0,12xy²+0,001y³2)(0,2a+30b)³=0,008a³+3,6a²b+540ab²+27000b³3)(1/7a-7c)³=1/343a³-3/7a²c+21ac²-343c³4)(0,3b-10c)³=0,027b³-2,7b²c+90bc²-1000c³5)(0,5x-2y)³=0,125x³-1,5x²y+6xy²-8y³6)(2/9n+9/2m)³=8/729n³+2/3n²m+27/2 nm²+729/8 m³1)x³-3x^2+3x-1=(x-1)³2)y³-3y²+3y-1=(y-1)³3)8+12p+6p²+p³=(2+p)³4)1-6q+12q²-8q³=(1-2q)³5)125-75a+15a²-a^3=(5-a)³6)0,008+0,12p+0,6p²+p³=(0,2+p)³