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Bogenbaizarina
@Bogenbaizarina
July 2022
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Помогите по химии пожалуйста 9-класс
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shakha2017
Verified answer
Дано:
m(смеси)=150г
m(CO2)=3г
______________
W(Fe)=?%
Решения:
Ar(C)=12
Mr(CO2)=44
x.............3г
C+O2=CO2
12г.........44г
x=12*3/44=36/44=0.818г
m(C)=0,818г
m(Fe)=m(смеси)-m(C)=
150-0.818=149.182г
W(Fe)=m(Fe)*100%/m(смеси)=
=149,182*100/150=99,4547%
1 votes
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Answers & Comments
Verified answer
Дано:m(смеси)=150г
m(CO2)=3г
______________
W(Fe)=?%
Решения:
Ar(C)=12
Mr(CO2)=44
x.............3г
C+O2=CO2
12г.........44г
x=12*3/44=36/44=0.818г
m(C)=0,818г
m(Fe)=m(смеси)-m(C)=
150-0.818=149.182г
W(Fe)=m(Fe)*100%/m(смеси)=
=149,182*100/150=99,4547%