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Slishkomtupaya
@Slishkomtupaya
October 2021
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Помогите пожалуйста, 2 вариант.
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igir12370
1) CosB=Cos(90-A)=SinA=0,1; 2) (SinA)^2=1-(CosA)^2; (SinA)^2=1-(7/25)^2; SinA=√576/625=24/25=0,96; 3) CosA=AC/AB; 0,5=AC/8; AC=0,5*8=4; 4) CosA=AC/AB=4/8=0,5; 5) SinA=0,5; A=30°; CosA=AC/AB; Cos30°=8/AB; AB=8 : √3/2=16/√3; S=AB*AC*SinA/2; S=8*16*0,5/2√3=32/√3; S=AB*CH/2; 32/√3=16*CH/2*√3; 8CH=32; CH=4;
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