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nancykovaliova1
@nancykovaliova1
August 2022
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помогите пожалуйста 200 б,г
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zhenyaM2002
Verified answer
Б) 25а²+20а+4 = (5а)² + 2*5а*2 + 2² = (5а +2)²
при а =2 ⇒ (5*2+2)² = 12² = 12*12= 144
г) 9 + 60b+100b² = 3² + 2*3*10b + (10b)² = (3+10b)²
при b=1 ⇒ (3 + 10*1)² = 13² = 13*13 = 169
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ПрофиЗнания
Б) 25a²+20a+4 = (5a)²+2*5a*2+ 2 ² = (5a+2)²
a=2
(5*2+2)²=12²=144
г) 9+60b +100b²= 3²+2*3*10b+(10b)² = (3+10b)²
b=1
(3+10*1)²=13²=169
0 votes
Thanks 1
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Answers & Comments
Verified answer
Б) 25а²+20а+4 = (5а)² + 2*5а*2 + 2² = (5а +2)²при а =2 ⇒ (5*2+2)² = 12² = 12*12= 144
г) 9 + 60b+100b² = 3² + 2*3*10b + (10b)² = (3+10b)²
при b=1 ⇒ (3 + 10*1)² = 13² = 13*13 = 169
a=2
(5*2+2)²=12²=144
г) 9+60b +100b²= 3²+2*3*10b+(10b)² = (3+10b)²
b=1
(3+10*1)²=13²=169