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a9444776
@a9444776
August 2021
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Помогите, пожалуйста, 332(6)
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MizoriesKun
X²+px+q=0
x₁+x₂=-p
x₁*x₂=q
√3-√2 ; 1/(√3-√2 )
1 3-2 (√3-√2 )(√3+√2 )
заметим ,что ------------ = ---------- = ----------------------- = √3+√2
√3-√2 √3-√2 √3-√2
q=(√3-√2 )(√3+√2 )=3-2=1
-p=(√3-√2 )+(√3+√2 ) =√3-√2 +√3+√2 =2√3
x²-2√3x+1=0
проверим
D=12-4=8 √D=√8= 2√2
x=(2√3+2√2)/2=√3+√2
x=(2√3-2√2)/2=√3-√2
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Answers & Comments
x₁+x₂=-p
x₁*x₂=q
√3-√2 ; 1/(√3-√2 )
1 3-2 (√3-√2 )(√3+√2 )
заметим ,что ------------ = ---------- = ----------------------- = √3+√2
√3-√2 √3-√2 √3-√2
q=(√3-√2 )(√3+√2 )=3-2=1
-p=(√3-√2 )+(√3+√2 ) =√3-√2 +√3+√2 =2√3
x²-2√3x+1=0
проверим
D=12-4=8 √D=√8= 2√2
x=(2√3+2√2)/2=√3+√2
x=(2√3-2√2)/2=√3-√2