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alinadjumatova1004
@alinadjumatova1004
August 2022
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Помогите пожалуйста!!!
359. Разложите на множители
2) ac-3bd+ad-3bc
4) 5ay-3bx+ax-15by
361. Вычислите
2) 139•15+18•139+15•261+18•261
4) ..
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olenka209079
359.
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Answers & Comments
359.


361.