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anastasyaposad
@anastasyaposad
August 2022
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Помогите пожалуйста 38.25 и 38.26...
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Universalka
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38.25
a) y = x√x = x * x^(1/2) = x^(3/2)
y ' = (x^3/2) ' = 3/2 x^1/2 = 3√x / 2
б) y = x² / √x = x² / x^1/2 = x ^3/2
y ' = (x^3/2) ' = 3/2x^1/2 = 3√x / 2
в) y = ³√x / x = x^1/3 /x = x^(-2/3)
y ' = (x^(-2/3) ' = - 2/3x^(- 5/3) = (-2 ) / 3 ³√x^5 = - 2/ 3x ³√x
г)y = x² ³√x = x ^(7/3)
y ' = 7/3 x ^4/3 = 7 ³√x^4 / 3 = 7x ³√x / 3
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Verified answer
38.25a) y = x√x = x * x^(1/2) = x^(3/2)
y ' = (x^3/2) ' = 3/2 x^1/2 = 3√x / 2
б) y = x² / √x = x² / x^1/2 = x ^3/2
y ' = (x^3/2) ' = 3/2x^1/2 = 3√x / 2
в) y = ³√x / x = x^1/3 /x = x^(-2/3)
y ' = (x^(-2/3) ' = - 2/3x^(- 5/3) = (-2 ) / 3 ³√x^5 = - 2/ 3x ³√x
г)y = x² ³√x = x ^(7/3)
y ' = 7/3 x ^4/3 = 7 ³√x^4 / 3 = 7x ³√x / 3