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sertim97
@sertim97
July 2022
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ПОМОГИТЕ ПОЖАЛУЙСТА 50 БАЛЛОВ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Даны точки М(2;1) и В(6;-2).Точка M-середина отрезка АВ. А)найдите координаты второго конца отрезка АВ.
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bzsr1
Verified answer
ХМ=(хА+xB)/2 хА=2*хМ-хВ = 4-6=-2
уВ=2*уМ-уВ = 2-(-2)=4
Ответ А(-2,4)
2 votes
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NukiDuki
Решение во вложении))
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Answers & Comments
Verified answer
ХМ=(хА+xB)/2 хА=2*хМ-хВ = 4-6=-2уВ=2*уМ-уВ = 2-(-2)=4
Ответ А(-2,4)