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dudchenko2701
@dudchenko2701
July 2022
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Помогите пожалуйста!!!
56а+7(а-4)^2 при а= корень из 15.
-12аb+(2а+3b)^2 при а=корень из 7, и при b=корень из 3.
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Vicus44ea
А) 56√15+7(√15-4)²=
56√15+7(15-8√15+16)=
56√15+105-56√15+112=
105+112=217.
б) -12•√7•√3+(2√7+3√3)²=
-12√21+(2√7)²+12√21+(3√3)²=
4•7+9•3=28+27=55.
2 votes
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Answers & Comments
56√15+7(15-8√15+16)=
56√15+105-56√15+112=
105+112=217.
б) -12•√7•√3+(2√7+3√3)²=
-12√21+(2√7)²+12√21+(3√3)²=
4•7+9•3=28+27=55.