Сумма углов треугольника равна 180°
∠A+∠B+∠C=180°
∠A=47°; ∠B=36°
47°+36°+∠C=180°⇒ 83°+∠C==180°
∠C=180°-83°=97°
Δ АВС=ΔDEF=ΔPMN ⇒
∠A=∠D=∠P=47°
∠B=∠E=∠M=36°
∠C=∠F=∠N=97°
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Verified answer
Сумма углов треугольника равна 180°
∠A+∠B+∠C=180°
∠A=47°; ∠B=36°
47°+36°+∠C=180°⇒ 83°+∠C==180°
∠C=180°-83°=97°
Δ АВС=ΔDEF=ΔPMN ⇒
∠A=∠D=∠P=47°
∠B=∠E=∠M=36°
∠C=∠F=∠N=97°