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prilenadena
@prilenadena
October 2021
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Помогите, пожалуйста :( #713
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m11m
713.
a) a²+13a+30=(a+10)(a+3)
a²+13a+30=0
D=169-120=49
a₁=(-13-7)/2=-10
a₂=-6/2=-3
б) a²+7a-30 =(a+10)(a-3)
a²+7a-30=0
D=49+120=169
a₁=(-7-13)/2=-10
a₂=6/2=3
в) a²-7a-30=(a+3)(a-10)
a²-7a-30=0
D=49+120=169
a₁=(7-13)/2=-3
a₂=20/2=10
г) b⁴+11b²+10=(b²+10)(b²+1)
b⁴+11b²+10=0
Пусть b²=x
x²+11x+10=0
D=121-40=81
x₁=(-11-9)/2=-20/2=-10
x₂=-2/2=-1
x²+11x+10=(x+10)(x+1)=(b²+10)(b²+1)
д) b⁴-9b²-10=(b²+1)(b²-10)
b⁴-9b²-10=0
Пусть b²=x
x²-9x-10=0
D=81+40=121
x₁=(9-11)/2=-1
x₂=20/2=10
x²-9x-10=(x+1)(x-10)=(b²+1)(b²-10)
е) b⁴+9b²-10=(b²+10)(b²-1)
b⁴+9b²-10=0
Пусть b²=x
x²+9x-10=0
D=81+40=121
x₁=(-9-11)/2=-10
x₂=2/2=1
x²+9x-10=(x+10)(x-1)=(b²+10)(b²-1)
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prilenadena
спасибо Вам огромное!!
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Answers & Comments
a) a²+13a+30=(a+10)(a+3)
a²+13a+30=0
D=169-120=49
a₁=(-13-7)/2=-10
a₂=-6/2=-3
б) a²+7a-30 =(a+10)(a-3)
a²+7a-30=0
D=49+120=169
a₁=(-7-13)/2=-10
a₂=6/2=3
в) a²-7a-30=(a+3)(a-10)
a²-7a-30=0
D=49+120=169
a₁=(7-13)/2=-3
a₂=20/2=10
г) b⁴+11b²+10=(b²+10)(b²+1)
b⁴+11b²+10=0
Пусть b²=x
x²+11x+10=0
D=121-40=81
x₁=(-11-9)/2=-20/2=-10
x₂=-2/2=-1
x²+11x+10=(x+10)(x+1)=(b²+10)(b²+1)
д) b⁴-9b²-10=(b²+1)(b²-10)
b⁴-9b²-10=0
Пусть b²=x
x²-9x-10=0
D=81+40=121
x₁=(9-11)/2=-1
x₂=20/2=10
x²-9x-10=(x+1)(x-10)=(b²+1)(b²-10)
е) b⁴+9b²-10=(b²+10)(b²-1)
b⁴+9b²-10=0
Пусть b²=x
x²+9x-10=0
D=81+40=121
x₁=(-9-11)/2=-10
x₂=2/2=1
x²+9x-10=(x+10)(x-1)=(b²+10)(b²-1)