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160929200
@160929200
July 2022
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помогите пожалуйста 8 и 3,очень срочно надо
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sangers1959
Verified answer
3.
lg(3x²+12x+19)-lg(3x+4)=lg10
lg(3x²+12x+19)=lg10+lg(3x+4)
lg(3x²+12x+19)=lg(10*(3x+4))
3x²+12x+19=30x+40
3x²-18x-21=0 D=576
x₁=7 x₂=-1.
Ответ: x₁=7 x₂=-1.
8.
3^(1+log₃(x²+y²))=15 ОДЗ: x-y>0 x>y
log₃(x²-y²)-log₃(x-y)=0
log₃((x-y)(x+y)/(x-y)=0 x≠y
log₃(x+y)=0
x+y=3⁰=1
y=1-x
log₃3^(1+log₃(x²+y²))=log₃15
1+log₃(x²+y²)=log₃15
log₃(x²+y²)=log₃15-1
log₃(x²+y²)=log₃15-log₃3
log₃(x²+y²)=log₃(15/3)
log₃(x²+y²)=log₃5
x²+y²=5
y=
1-x ⇒
x²+(1-x)²=5
x²+1-2x+x²=5
2x²-2x-4=0 |÷2
x²-x-2=0 D=9
x₁=2 y=1-2=-1
x₂=-1 y=1-(-1)=2 ∉ по ОДЗ (x>y)
Ответ: x=2 y=-1.
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160929200
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sangers1959
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Answers & Comments
Verified answer
3.lg(3x²+12x+19)-lg(3x+4)=lg10
lg(3x²+12x+19)=lg10+lg(3x+4)
lg(3x²+12x+19)=lg(10*(3x+4))
3x²+12x+19=30x+40
3x²-18x-21=0 D=576
x₁=7 x₂=-1.
Ответ: x₁=7 x₂=-1.
8.
3^(1+log₃(x²+y²))=15 ОДЗ: x-y>0 x>y
log₃(x²-y²)-log₃(x-y)=0
log₃((x-y)(x+y)/(x-y)=0 x≠y
log₃(x+y)=0
x+y=3⁰=1
y=1-x
log₃3^(1+log₃(x²+y²))=log₃15
1+log₃(x²+y²)=log₃15
log₃(x²+y²)=log₃15-1
log₃(x²+y²)=log₃15-log₃3
log₃(x²+y²)=log₃(15/3)
log₃(x²+y²)=log₃5
x²+y²=5
y=1-x ⇒
x²+(1-x)²=5
x²+1-2x+x²=5
2x²-2x-4=0 |÷2
x²-x-2=0 D=9
x₁=2 y=1-2=-1
x₂=-1 y=1-(-1)=2 ∉ по ОДЗ (x>y)
Ответ: x=2 y=-1.