ПОМОГИТЕ ПОЖАЛУЙСТА 80 БАЛЛОВ ДАЮ НОМЕРА=№163 ,№164. Created by nikitamol2018. algebra-ru

ПОМОГИТЕ ПОЖАЛУЙСТА 80 БАЛЛОВ ДАЮ НОМЕРА=№163 ,№164...

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August 2022 1 10 Report

ПОМОГИТЕ ПОЖАЛУЙСТА 80 БАЛЛОВ ДАЮ НОМЕРА=№163 ,№164

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$163)\ \ x^2-7=(x-\sqrt7)(x+\sqrt7)\\\\5-c^2=(\sqrt5-c)(\sqrt5+c)\\\\4a^2-3=(2a-\sqrt3)(2a+\sqrt3)\\\\11-16b^2=(\sqrt{11}-4b)(\sqrt{11}+4b)\\\\y-3=(\sqrt{y}-\sqrt3)(\sqrt{y}+\sqrt3)\\\\x-y=(\sqrt{x}-\sqrt{y})(\sqrt{x}+\sqrt{y})$

$164)\ \ 3+\sqrt3=\sqrt3\cdot (\sqrt3+1)\\\\10-2\sqrt{10}=\sqrt{10}\cdot (\sqrt{10}-2)=\sqrt{10}\cdot \sqrt2\cdot (\sqrt5-\sqrt2)=2\sqrt5\cdot (\sqrt5-\sqrt2)\\\\\sqrt{x}+x=\sqrt{x}\cdot (\sqrt{x}+1)\\\\a-5\sqrt{a}=\sqrt{a}\cdot (\sqrt{a}-5)\\\\\sqrt{a}-\sqrt{2a}=\sqrt{a}\cdot (1-\sqrt2)\\\\\sqrt{3m}+\sqrt{5m}=\sqrt{m}\cdot (\sqrt3+\sqrt5)\\\\\sqrt{14}-\sqrt{7}=\sqrt{7}\cdot (\sqrt2-1)\\\\\sqrt{33}+\sqrt{22}=\sqrt{11}\cdot (\sqrt3+\sqrt2)$

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