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maiko2
@maiko2
July 2022
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ПОМОГИТЕ ПОЖАЛУЙСТА!!!!
cos2a-sin2a*ctga
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BOR48
Cos2α - sin2α*ctqα =cos2α - sin2α*cosα /sinα =
(cos2α*sinα - sin2α*cosα)/sinα= -(sin2α*cosα - cos2α*sinα)/sinα =
- sin(2α -α) /sinα = - sinα /sinα
=
-1.
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maiko2
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Answers & Comments
(cos2α*sinα - sin2α*cosα)/sinα= -(sin2α*cosα - cos2α*sinα)/sinα =
- sin(2α -α) /sinα = - sinα /sinα = -1.