Помогите пожалуйста Дам вам 30 каштанчиков(баллов). Created by you2778. algebra-ru

Помогите пожалуйста Дам вам 30 каштанчиков(баллов)...

you2778 @you2778

July 2022 1 2 Report

Помогите пожалуйста
Дам вам 30 каштанчиков(баллов)

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NNNLLL54

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$a)\ \ \dfrac{4}{a}+\dfrac{a-4}{a+3}=\dfrac{4a+12+a^2-4a}{a(a+3)}=\dfrac{a^2+12}{a(a+3)}\\\\\\b)\ \ \dfrac{2x^2}{x^2-4}-\dfrac{2x}{x+2}=\dfrac{2x^2-2x\, (x-2)}{(x-2)(x+2)}=\dfrac{4x}{x^2-4}$

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you2778 July 2023 | 0 Ответы

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