x²−5x> −6
x²−5x+6 >0
D=25-24=1
x₁=(5+1)/2=3
x₂=(5-1)/2=2
+ - +
------------2-------------3----------------
x∈(−∞;2)∪(3;+∞)
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x²−5x> −6
x²−5x+6 >0
D=25-24=1
x₁=(5+1)/2=3
x₂=(5-1)/2=2
+ - +
------------2-------------3----------------
x∈(−∞;2)∪(3;+∞)