Ответ:
y'(π/6)=-3
Пошаговое объяснение:
у'=(sin3x+cos3x)'=cos3x × (3x)'-sin3x × (3x)'=cos3x × 3-sin3x × 3=3 ×(cos3x-sin3x)
y'(π/6)=3 × (cos(3 ×π/6)-sin(3 ×π/6))=3 ×(cos π/2-sin π/2)=3 ×(0-1)=-3
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Ответ:
y'(π/6)=-3
Пошаговое объяснение:
у'=(sin3x+cos3x)'=cos3x × (3x)'-sin3x × (3x)'=cos3x × 3-sin3x × 3=3 ×(cos3x-sin3x)
y'(π/6)=3 × (cos(3 ×π/6)-sin(3 ×π/6))=3 ×(cos π/2-sin π/2)=3 ×(0-1)=-3