August 2021 0 19 Report
ПОМОГИТЕ ПОЖАЛУЙСТА! Для сгорания 3 л смеси метана и пропана требуется 12 л кислорода. Найдите объёмную долю метана в смеси.
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
srochno osushestvite cepochku prevrashenij ciklogeksan gtbenzol gtiz
Answer
srochnopomogite pozhalujsta osushestvite cepochku prevrashenij karbid kalc
Answer
a couple of month ago received a letter out of the blue saying i'd won...
Answer
pomogite pozhalujsta ochen nuzhno napishite uravneniya reakcij polucheniya tereftale
Answer
pozhalujsta dokazhite tozhdestvo cos4asin2acos2asin2a1
Answer
4sina3cosa
Answer
1cos a tg a
Answer
poluchite iz etilenglikolya 246 trinitrotoluol
Answer
pomogite pozhalujsta srochno poluchit iz etilenglikolya glicerin v neskolko r
Answer
30 ballov pomogite pozhalujsta cherez diagonal kvadrata provedena ploskost pod
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.