sin⁴ t - 2sin²t cos²t + cos⁴ t = (sin² t - cos²t )² = (sin²t - 1 + sin²t)² = (2sin²t - 1)² = (1 - 2sin²t)² доказано
Ответ:
Доказать: sin⁴t-2·sin²t·cos²t+cos⁴t=(1-2·sin²t)²
Доказательство:
sin⁴t-2·sin²t·cos²t+cos⁴t=(cos²t-sin²t)²=((1-sin²t)-sin²t)²=(1-sin²t-sin²t)²=(1-2·sin²t)²
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Verified answer
sin⁴ t - 2sin²t cos²t + cos⁴ t = (sin² t - cos²t )² = (sin²t - 1 + sin²t)² = (2sin²t - 1)² = (1 - 2sin²t)² доказано
Verified answer
Ответ:
Доказать: sin⁴t-2·sin²t·cos²t+cos⁴t=(1-2·sin²t)²
Доказательство:
sin⁴t-2·sin²t·cos²t+cos⁴t=(cos²t-sin²t)²=((1-sin²t)-sin²t)²=(1-sin²t-sin²t)²=(1-2·sin²t)²