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MalmakovMurad
@MalmakovMurad
June 2022
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Помогите пожалуйста
f(x)=2x^2-x^4
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AlinaCliff
·
F(x)=3-2x-x^2
F(x)=-x^2-2x+3
-x^2-2x+3=0 (*(-1))
x^2+2x-3=0
Д=b^2-4ac=4+12=16
x1=(-2+4)/2=1
x2=(-2-4)/2=-3
Ответ: х1,2=1, -3
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Answers & Comments
F(x)=3-2x-x^2
F(x)=-x^2-2x+3
-x^2-2x+3=0 (*(-1))
x^2+2x-3=0
Д=b^2-4ac=4+12=16
x1=(-2+4)/2=1
x2=(-2-4)/2=-3
Ответ: х1,2=1, -3