Ответ:
Объяснение:
a)
y=x*cosx
y'=(x*cosx)'=cosx-x*sinx.
б)
y=x²/(1+x)
y'=(x²/(1+x))'=((x²)'*(x+1)-x²*(x+1)')/(x+1)²=(2x*(x+1)-x²)/(x+1)²=
=(2x²+2x-x²)/(x+1)²=(x²+2x)/(x+1)²=x*(x+2)/(x+1)².
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
Объяснение:
a)
y=x*cosx
y'=(x*cosx)'=cosx-x*sinx.
б)
y=x²/(1+x)
y'=(x²/(1+x))'=((x²)'*(x+1)-x²*(x+1)')/(x+1)²=(2x*(x+1)-x²)/(x+1)²=
=(2x²+2x-x²)/(x+1)²=(x²+2x)/(x+1)²=x*(x+2)/(x+1)².