1)(у-8)(2у+1)-(3у+1)(у-6)=-у(квадрат)+2у-2.
2)(2х-3у)(2х+3у)+(3х+2у)(3х-2у)=13х(квадрат)-13у(квадрат).
3)(х+1)^2-(x-3)(x+3)=-x(квадрат)+2х+11.
4)(у-4)(у+3)-(у-6)^2=y(y-3)
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Answers & Comments
1)(у-8)(2у+1)-(3у+1)(у-6)=-у(квадрат)+2у-2.
2)(2х-3у)(2х+3у)+(3х+2у)(3х-2у)=13х(квадрат)-13у(квадрат).
3)(х+1)^2-(x-3)(x+3)=-x(квадрат)+2х+11.
4)(у-4)(у+3)-(у-6)^2=y(y-3)