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dkoltunka
@dkoltunka
July 2022
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Помогите пожалуйста
lg (2x^2)=2lg (x-2)
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stason28042000
2x²=(x-2)² ОДЗ: (2x²)>0; (x-2)> 0
2x²=x²-4x+4
x²+4x-4=0
D=4²-4(1*-4)=36
x(1,2)=-4±√36/2=
x(1)= -5 (п.к.)
x(2)= 1
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dkoltunka
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Answers & Comments
2x²=x²-4x+4
x²+4x-4=0
D=4²-4(1*-4)=36
x(1,2)=-4±√36/2=
x(1)= -5 (п.к.)
x(2)= 1