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Игорь3773
@Игорь3773
July 2022
2
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ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!
найдите корни уравнения (2x-3)(1-x)=x^2-3x
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Anastasia199999
2х-2х^2-3+3=х^2-3х
2х-2х^2-х^2+3х=3-3
-3х^2+5х=0/*(-1)
3х^2-5х=0
х(3х-5)=0
х=0 или 3х-5=0
3х=5
х=5/3
1 votes
Thanks 0
Игорь3773
в 1 строке 3 x должно быть
Игорь3773
перед=
danakalistratova
(2x-3)(1-x)= x2-3x
x=1 1/3- корень7/3
x=корень7/3 +1 1/3
1 votes
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Answers & Comments
2х-2х^2-х^2+3х=3-3
-3х^2+5х=0/*(-1)
3х^2-5х=0
х(3х-5)=0
х=0 или 3х-5=0
3х=5
х=5/3
x=1 1/3- корень7/3
x=корень7/3 +1 1/3