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bonton
@bonton
July 2022
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помогите, пожалуйста! Найдите значение выражения
1) 2b^2-14b+1, если b+√b -3= 0 и
2) найдите |a-b|, если a+b=2√6, a*b=2
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DariosI
Verified answer
1)
b≥0
b+√b-3=0
√b=3-b
(√b)²=(3-b)²
b=9-6b+b²
b²-7b+9=0
b²-7b=-9
2b²-14b+1=2(b²-7b)+1=2*(-9)+1=-18+1=-17
2)la-bl
a+b=2√6
a*b=2
b=2√6-a
a(2√6-a)=2
2√6a-a²=2
a²-2√6*a+2=0
D=(2√6)²-4*2=4*6-8=24-8=16
a₁=(2√6-4)/2=√6-2 b₁=2√6-√6+2=√6+2
a₂=
(2√6+4)/2=√6+2 b
₂=2√6-√6-2=√6-2
la-bl=l
√6-2-√6-2l=l-4l=4
la-bl=l
√6+2-√6+2l=4
11 votes
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bonton
огромное спасибо!!!
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Answers & Comments
Verified answer
1)b≥0
b+√b-3=0
√b=3-b
(√b)²=(3-b)²
b=9-6b+b²
b²-7b+9=0
b²-7b=-9
2b²-14b+1=2(b²-7b)+1=2*(-9)+1=-18+1=-17
2)la-bl
a+b=2√6
a*b=2
b=2√6-a
a(2√6-a)=2
2√6a-a²=2
a²-2√6*a+2=0
D=(2√6)²-4*2=4*6-8=24-8=16
a₁=(2√6-4)/2=√6-2 b₁=2√6-√6+2=√6+2
a₂=(2√6+4)/2=√6+2 b₂=2√6-√6-2=√6-2
la-bl=l√6-2-√6-2l=l-4l=4
la-bl=l√6+2-√6+2l=4