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Angelocek32
@Angelocek32
August 2022
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Помогите пожалуйста найти промежуток возрастания функции у=-3(х-1)^2+2
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m11m
Y=-3(x-1)² +2
y' = -6(x-1)
-6(x-1)=0
x-1=0
x=1
+ ↑ - ↓
----------- 1 -----------
При х∈(-∞; 1] функция возрастает.
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Answers & Comments
y' = -6(x-1)
-6(x-1)=0
x-1=0
x=1
+ ↑ - ↓
----------- 1 -----------
При х∈(-∞; 1] функция возрастает.