(y-c+3)²+2(c-y-3)(y+c+3)+(y+c+3)² = (y-c+3)²-2(y-с+3)(y+c+3)+(y+c+3)²
(y-c+3-(y+c+3))² = (y-c+3-y-c-3)² = (-2c)²
Подставим значения: (-2с)² = (-2*0.2)² = (-0.4)² =0.16
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(y-c+3)²+2(c-y-3)(y+c+3)+(y+c+3)² = (y-c+3)²-2(y-с+3)(y+c+3)+(y+c+3)²
(y-c+3-(y+c+3))² = (y-c+3-y-c-3)² = (-2c)²
Подставим значения: (-2с)² = (-2*0.2)² = (-0.4)² =0.16