Home
О нас
Products
Services
Регистрация
Войти
Поиск
4Mironchik7
@4Mironchik7
July 2022
1
1
Report
Помогите пожалуйста номер 66 и 67
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
FabulousTurtle
66. 1)
2)
3)
4)
5) (8^1/15)^-5 = 8^1/15*-5 = 8^-1/3 = 1/2
67. 1) 9^2/5 * 27^2/5 = (3^2)^2/5 * (3^3)^2/5 = (3^2*2/5) * (3^3*2/5) = 3^4/5 * 3^6/5 = 3^4/5+6/5 = 3^10/5 = 3^2 = 9
2) 7^2/3 * 49^2/3 = 7^2/3 * (7^2)^2/3 = 7^2/3 * 7^2*2/3 = 7^2/3 * 7^4/3 = 7^2/3+4/3 = 7^6/3 = 7^2 = 49
3) 144^3/4 ÷ 9^3/4 = (144÷9)^3/4 = 16^3/4 = (2^4)^3/4 = 2^4*3/4 = 2^3 = 8
4) 150^3/2 ÷ 6^3/2 = (150÷6)^3/2 = 25^3/2 = (5^2)^3/2 = 5^2*3/2 = 5^3 = 125
1 votes
Thanks 1
4Mironchik7
А вы можете объяснить , как под цифрой 4 вы возвели в степень?
FabulousTurtle
В каком номере?
4Mironchik7
66
FabulousTurtle
Так как в степени стоит "-", то чтобы его убрать нужно 1/(9^1/2), 9^1/2 = 3, отсюда и получается 1/3
4Mironchik7
Спасибо
More Questions From This User
See All
4Mironchik7
August 2022 | 0 Ответы
pomogite reshit nomer 6893c2c891fa345ce0f273a050eedce275 99507
Answer
4Mironchik7
August 2022 | 0 Ответы
pomogite reshit eti primery esli mozhno to s podrobnym obyasneniem
Answer
4Mironchik7
August 2022 | 0 Ответы
srochno pomogite reshit hotya by 1 variant
Answer
4Mironchik7
July 2022 | 0 Ответы
pomogite sdelat nomer 1 i 2 po algebre s resheniem
Answer
4Mironchik7
July 2022 | 0 Ответы
pomogite s pervymi dvumyaee4f2539052342010abada83af04e32c 13205
Answer
4Mironchik7
March 2022 | 0 Ответы
pomogite srochno pervye dva zadaniya ochen nuzhno
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите пожалуйста номер 66 и 67..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2)
3)
4)
5) (8^1/15)^-5 = 8^1/15*-5 = 8^-1/3 = 1/2
67. 1) 9^2/5 * 27^2/5 = (3^2)^2/5 * (3^3)^2/5 = (3^2*2/5) * (3^3*2/5) = 3^4/5 * 3^6/5 = 3^4/5+6/5 = 3^10/5 = 3^2 = 9
2) 7^2/3 * 49^2/3 = 7^2/3 * (7^2)^2/3 = 7^2/3 * 7^2*2/3 = 7^2/3 * 7^4/3 = 7^2/3+4/3 = 7^6/3 = 7^2 = 49
3) 144^3/4 ÷ 9^3/4 = (144÷9)^3/4 = 16^3/4 = (2^4)^3/4 = 2^4*3/4 = 2^3 = 8
4) 150^3/2 ÷ 6^3/2 = (150÷6)^3/2 = 25^3/2 = (5^2)^3/2 = 5^2*3/2 = 5^3 = 125