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mashulyasalo
@mashulyasalo
August 2022
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Помогите пожалуйста!
Нужно решить уравнение:
х(х-2)(х+1)= х в квадрате(х-1)
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Answers & Comments
grigandal625
X(x-2)(x+1)=x²(x-1)
x(x-2)(x+1)-x²(x-1)=0
x(
(x-2)(x+1)-x(x-1))=0
x(x²-x-2-x²+x)=0
x(-2)=0
x=0
ответ: 0
3 votes
Thanks 2
mashulyasalo
Спасибо!
gvikamiki
Х³+х²-2х²-2х=х³-х²
х³+х²-2х²-2х-х³+х²=0
-2х=0
х=0
1 votes
Thanks 1
mashulyasalo
Спасибо.
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Answers & Comments
x(x-2)(x+1)-x²(x-1)=0
x((x-2)(x+1)-x(x-1))=0
x(x²-x-2-x²+x)=0
x(-2)=0
x=0
ответ: 0
х³+х²-2х²-2х-х³+х²=0
-2х=0
х=0