Home
О нас
Products
Services
Регистрация
Войти
Поиск
tima0688
@tima0688
July 2022
1
2
Report
помогите пожалуйста. Нужно срочно заранее спасибо!!! нужно решить 2; 3 и 4 пример
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Miа16
Ответ:
2)
3)
4)
1 votes
Thanks 1
More Questions From This User
See All
tima0688
July 2022 | 0 Ответы
5-topshiriq.O'zigizni tekshiring. Berilgan asarlar o'zbek adiblarining qaysi bir...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "помогите пожалуйста. Нужно срочно заранее спасибо!!! нужно решить 2; 3 и 4 приме..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
2)![\frac{a+b}{a-b} - \frac{a-b}{a+b} =\frac{(a+b)^2-(a-b)^2}{(a-b)*(a+b)} = \frac{2b*2a}{a^2-b^2} = \frac{4ab}{a^2-b^2} \frac{a+b}{a-b} - \frac{a-b}{a+b} =\frac{(a+b)^2-(a-b)^2}{(a-b)*(a+b)} = \frac{2b*2a}{a^2-b^2} = \frac{4ab}{a^2-b^2}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%2Bb%7D%7Ba-b%7D%20-%20%5Cfrac%7Ba-b%7D%7Ba%2Bb%7D%20%3D%5Cfrac%7B%28a%2Bb%29%5E2-%28a-b%29%5E2%7D%7B%28a-b%29%2A%28a%2Bb%29%7D%20%3D%20%5Cfrac%7B2b%2A2a%7D%7Ba%5E2-b%5E2%7D%20%3D%20%5Cfrac%7B4ab%7D%7Ba%5E2-b%5E2%7D)
3)![\frac{2a-4}{3b} * \frac{6b}{a-2} = 2(a-2)*\frac{2}{a-2} =2*2=4 \frac{2a-4}{3b} * \frac{6b}{a-2} = 2(a-2)*\frac{2}{a-2} =2*2=4](https://tex.z-dn.net/?f=%5Cfrac%7B2a-4%7D%7B3b%7D%20%2A%20%5Cfrac%7B6b%7D%7Ba-2%7D%20%3D%202%28a-2%29%2A%5Cfrac%7B2%7D%7Ba-2%7D%20%3D2%2A2%3D4)
4)![\frac{a^2-b^2}{b^2} : \frac{a+b}{b} = \frac{(a-b)*(a+b)}{b^2} * \frac{b}{a+b} = \frac{a-b}{b} \frac{a^2-b^2}{b^2} : \frac{a+b}{b} = \frac{(a-b)*(a+b)}{b^2} * \frac{b}{a+b} = \frac{a-b}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E2-b%5E2%7D%7Bb%5E2%7D%20%3A%20%5Cfrac%7Ba%2Bb%7D%7Bb%7D%20%3D%20%5Cfrac%7B%28a-b%29%2A%28a%2Bb%29%7D%7Bb%5E2%7D%20%2A%20%5Cfrac%7Bb%7D%7Ba%2Bb%7D%20%3D%20%5Cfrac%7Ba-b%7D%7Bb%7D)