Помогите пожалуйста, очень надо) С 7.6.40 До 7.6.46. Created by annamel2020. matematika-ru

Помогите пожалуйста, очень надо) С 7.6.40 До 7.6.46...

annamel2020 @annamel2020

July 2022 1 5 Report

Помогите пожалуйста, очень надо)
С 7.6.40
До 7.6.46

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гюйс

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7,40 \\ \\.....=(x+1)* \frac{x-1}{(x+1)(x+1)}= \frac{x-1}{x+1} \\ x=4 \\ \frac{4-1}{4+1}= \frac{3}{5} =0.6 \\ \\ 7.41 \\ .....= \frac{7+5}{35a}* \frac{a^{2} }{8}= \frac{3a}{70} \\ a= -4,2 \\ -\frac{3*4.2}{70}=-12,6:70=-0.18 \\ \\ 7.42 \\ .......= \frac{9}{20a} \frac{a^{2} }{9}= \frac{a}{20} \\ a=7.8 \\ \frac{7.8}{20} =0.39 \\ \\ 7.43 \\ .....= \frac{b^{2}-49a^{2} }{7ab}* \frac{1}{b+7a}= \frac{(b+7a)(b-7a)}{7ab}* \frac{1}{b+7a}= \frac{b-7a}{7ab} \\ a= \frac{1}{7} , b= \frac{1}{6} \\ [/tex] $\frac{ \frac{1}{6}-7* \frac{1}{7} }{7* \frac{1}{7}* \frac{1}{6} } = \frac{ \frac{1}{6}-1 }{ \frac{1}{6} } =- \frac{ \frac{5}{6} }{ \frac{1}{6} } =-5 \\ \\ 7.44 \\ .....= \frac{4b^{2} -25 a^{2} }{10ab}* \frac{1}{2b+5a}= \frac{(2b+5a)(2b-5a)}{10ab}* \frac{1}{2b+5a}= \frac{2b-5a}{10ab} \\ a= \frac{1}{5}, b= \frac{1}{9} \\ \frac{2* \frac{1}{9}-5* \frac{1}{5} }{10* \frac{1}{5} * \frac{1}{9} } = \frac{ \frac{2}{9}-1 }{ \frac{2}{9} } =- \frac{7}{9} * \frac{9}{2} =- \frac{7}{2}=-3.5 \\ \\ 7.45 \\$ $[tex] ......=\frac{ y^{2} -4 x^{2} }{2xy} * \frac{1}{y+2x} = \frac{(y-2x)(y+2x)}{2xy(y+2x)}= \frac{y-2x}{2xy} \\ x= \frac{1}{7} , y= \frac{1}{8} \\ \frac{ \frac{1}{8}-2* \frac{1}{7} }{2* \frac{1}{7} *\frac{1}{8} } = \frac{ \frac{7}{56}- \frac{16}{56} }{ \frac{1}{28} } =- \frac{9}{56}* 28=-4.5$
$\\ 7.46 \\ .......= \frac{9y^{2} - 4x^{2} }{6xy} * \frac{1}{3y+2x} = \frac{(3y+2x)(3y-2x)}{6xy(3y+2x)}= \frac{3y-2x}{6xy} \\ x= \frac{1}{8} , y= \frac{1}{6} \\ \frac{3* \frac{1}{6}-2* \frac{1}{8} }{6* \frac{1}{8} * \frac{1}{6} } = \frac{ \frac{1}{4} }{ \frac{1}{8} } = \frac{1}{4} *8=2$

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