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CherryPigs
@CherryPigs
June 2022
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помогите пожалуйста, очень надо
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армения20171
5)cosa=1/3;1+tg^2(a)=1/cos^2(a)
tg^2(a)=1/(1/3)^2-1=9-1=8
tga=√8=2√2;tga=-√8=-2√2
ответ 2√2
6)sinA=2/5;sinB=?
sinB=sin(90°-<A)=cosA=√(1-sin^2A)=
√(1-4/25)=√(21/25)=√21/5
ответ√21/5
7)sin30°•cos45°•tg60°=1/2*√2/2*√3=
√6/4
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Answers & Comments
tg^2(a)=1/(1/3)^2-1=9-1=8
tga=√8=2√2;tga=-√8=-2√2
ответ 2√2
6)sinA=2/5;sinB=?
sinB=sin(90°-<A)=cosA=√(1-sin^2A)=
√(1-4/25)=√(21/25)=√21/5
ответ√21/5
7)sin30°•cos45°•tg60°=1/2*√2/2*√3=
√6/4