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Krab1kan
@Krab1kan
June 2022
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Помогите пожалуйста очень нужна помощь!
АЛГЕБРА 8 КЛАСС ТЕОРЕМА ВИЕТА
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au456
Verified answer
X^2-13x+5=0
по теореме Виетта
x1+x2=13
x1x2=5
1/x1+1/x2=(x1+x2)/(x1x2)= 13/5
(x1-x2)^2= (x1+x2)^2-4x1x2=169-20=149
1/x1^2+1/x2^2=(x1^2+x2^2)/(x1x2)^2=((x1+x2)^2-2x1x2)/(x1x2)^2=(169-10)/25=159/25
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Answers & Comments
Verified answer
X^2-13x+5=0по теореме Виетта
x1+x2=13
x1x2=5
1/x1+1/x2=(x1+x2)/(x1x2)= 13/5
(x1-x2)^2= (x1+x2)^2-4x1x2=169-20=149
1/x1^2+1/x2^2=(x1^2+x2^2)/(x1x2)^2=((x1+x2)^2-2x1x2)/(x1x2)^2=(169-10)/25=159/25