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nlalkan
@nlalkan
July 2022
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помогите пожалуйста , очень прошу , заранее спасибо !!!
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nKrynka
[2*(x+ y) - xy] / 2xy = 0
y = 3x - 3
[2*x + 2*( 3x - 3) - x(3x - 3)] / 2x(3x - 3) = 0
2x(3x - 3) ≠ 0, x₁≠ 0; x₂ ≠ 1
2x + 6x - 6 - 3x² + 3x = 0
3x² - 11x + 6 = 0
D = 121 - 4*3*6 = 49
x₁ = (11 - 7)/6
x₁ = 2/3
x₂ = (11 + 7)/6
x₂ = 3
y₁ = 3*(2/3) - 3
y₁ = 2 - 3
y₁ = - 1
y₂ = 3*3 - 3
y₂ = 6
Ответ: (2/3;-1) (3;6)
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Answers & Comments
y = 3x - 3
[2*x + 2*( 3x - 3) - x(3x - 3)] / 2x(3x - 3) = 0
2x(3x - 3) ≠ 0, x₁≠ 0; x₂ ≠ 1
2x + 6x - 6 - 3x² + 3x = 0
3x² - 11x + 6 = 0
D = 121 - 4*3*6 = 49
x₁ = (11 - 7)/6
x₁ = 2/3
x₂ = (11 + 7)/6
x₂ = 3
y₁ = 3*(2/3) - 3
y₁ = 2 - 3
y₁ = - 1
y₂ = 3*3 - 3
y₂ = 6
Ответ: (2/3;-1) (3;6)