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lyubabakhtigor
@lyubabakhtigor
August 2021
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помогите пожалуйста очень прошу
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tan4ik3107
А)
9ху/ 2а⁴в³ * (-ав/3ху)²=
3² ху / 2а⁴в³ * (-а²в²/3²х²у²)=
1 / 2а²в * (-1/ ху)=
-1/2* 1/ а²*в*х*у=
(2*а²*в*х*у)^-1
^ - в степени
б)
(а/а+1 +1) : (1- 3а²/1-а²)=
(а+а+1 / а+1) : (1- 3а²/(1-а)(1+а)=
(2а+1 / а+1) * ((1-а)(1+а) / 1- 3а²) =
(2а+1 ) * ((1-а) / 1- 3а²) =
(2а+1 )(1-а) / 1- 3а² =
2а-2а²+1-а / 1- 3а² =
а-2а²+1 / 1- 3а²
в)
((х-у)/(х+у) + (х+у)/(х-у)) : (х/у + у/х)=
((х-у)² + (х+у)²/(х+у)(х-у)) : (х² + у²/ху)=
((х²-2ху+у²+х²+2ху+у²)/(х²-у²)) * (ху/х²+у²)=
((2х²+2у²)/(х²-у²)) * (ху/х²+у²)=
(2(х²+у²)/(х²-у²)) * (ху/х²+у²)=
2ху / х²-у²
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Answers & Comments
9ху/ 2а⁴в³ * (-ав/3ху)²=
3² ху / 2а⁴в³ * (-а²в²/3²х²у²)=
1 / 2а²в * (-1/ ху)=
-1/2* 1/ а²*в*х*у=
(2*а²*в*х*у)^-1
^ - в степени
б)
(а/а+1 +1) : (1- 3а²/1-а²)=
(а+а+1 / а+1) : (1- 3а²/(1-а)(1+а)=
(2а+1 / а+1) * ((1-а)(1+а) / 1- 3а²) =
(2а+1 ) * ((1-а) / 1- 3а²) =
(2а+1 )(1-а) / 1- 3а² =
2а-2а²+1-а / 1- 3а² =
а-2а²+1 / 1- 3а²
в)
((х-у)/(х+у) + (х+у)/(х-у)) : (х/у + у/х)=
((х-у)² + (х+у)²/(х+у)(х-у)) : (х² + у²/ху)=
((х²-2ху+у²+х²+2ху+у²)/(х²-у²)) * (ху/х²+у²)=
((2х²+2у²)/(х²-у²)) * (ху/х²+у²)=
(2(х²+у²)/(х²-у²)) * (ху/х²+у²)=
2ху / х²-у²