4) q=1/5, b1=25, S=b1/(1-q) S=25/(1-1/5)=25:4/5=125/4=31,25.
2.a)b1=100,b3=25,b2=?
b2²=b1·b3⇒ b2=√b1·b3=√100·25=10·5=50.
б)Sn=b1(1-q^n) / (1-q)
189=3(1-2^n) /(1-2)
189=-3+3·2^n
192=3·2^n
2^n=64
2^n=2^6⇒ n=6.
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4) q=1/5, b1=25, S=b1/(1-q) S=25/(1-1/5)=25:4/5=125/4=31,25.
2.a)b1=100,b3=25,b2=?
b2²=b1·b3⇒ b2=√b1·b3=√100·25=10·5=50.
б)Sn=b1(1-q^n) / (1-q)
189=3(1-2^n) /(1-2)
189=-3+3·2^n
192=3·2^n
2^n=64
2^n=2^6⇒ n=6.